What is the change in momentum of a car weighing 1500 kg when its speed increases from 36 km/h to 72 km/h uniformly?

momentum=mass*change velocity

= 1500kg*(72-36)km/hr
= 1500*3600/3600=1500 N-s

What is change in momentum of a car weight its 1500kg when it speed increase from 36km per hour to 72km per hour uniform. Subject - physics

To find the change in momentum of the car, we need to first calculate the initial momentum and the final momentum.

Momentum (p) is defined as the product of the mass (m) and the velocity (v) of an object:

p = m * v

Given:
Mass of the car (m) = 1500 kg
Initial velocity (v1) = 36 km/h
Final velocity (v2) = 72 km/h

First, we need to convert the velocities from km/h to m/s, as momentum is calculated using SI units:

1 km/h = 0.2778 m/s

Initial velocity (v1) = 36 km/h * 0.2778 m/s = 10 m/s
Final velocity (v2) = 72 km/h * 0.2778 m/s = 20 m/s

Now we can calculate the initial momentum (p1) and the final momentum (p2) using the momentum formula:

p1 = m * v1 (Initial momentum)
p2 = m * v2 (Final momentum)

p1 = 1500 kg * 10 m/s = 15000 kg*m/s
p2 = 1500 kg * 20 m/s = 30000 kg*m/s

Finally, we can find the change in momentum (Δp) by subtracting the initial momentum from the final momentum:

Δp = p2 - p1

Δp = 30000 kg*m/s - 15000 kg*m/s = 15000 kg*m/s

Therefore, the change in momentum of the car is 15000 kg*m/s when its speed increases from 36 km/h to 72 km/h uniformly.

1500