Iam a number between 4 and 10. My dicimal is in tenths l. The sum if my digit is 10.What number i can be?
looks like a decimal number with 2 decimal places
4.1x , sum has to be 10 , so 4.15 ,
5.1x , ---> 5.14
6.1x, ---> 6.13
7.1x ----> 7.12
8.1x ----> 8.11
could it be 3 decimal places?
4.1xx --- 4.132, or 4.114 or 4.123 or 4.105
etc
lot's of cases!
and even lots of apostrophes!
(well, one, anyway)
To find the number that meets the given criteria, let's break down the information step by step:
1. The number is between 4 and 10.
This means the number falls within the range of 4 < x < 10.
2. The number has a decimal in tenths place.
The tenths place is the first digit after the decimal point. Therefore, the number can be expressed in the format x.y where y represents the tenths place.
3. The sum of the digits is 10.
Since our number only has one decimal digit, let's call it y. The sum of the digits of x.y is x + y. Based on the given information, we know that the sum of the digits (x + y) is equal to 10.
Now, let's consider the possible options for y:
For y = 0, the sum of the digits would be x + 0 = x. However, since x is a whole number between 4 and 10, the sum x cannot be equal to 10. Therefore, y cannot be 0.
For y = 1, the sum of the digits would be x + 1. Since we are looking for the sum to be equal to 10, x + 1 = 10. Subtracting 1 from both sides, we find that x = 9. Therefore, if y = 1, the number will be 9.1.
For y = 2, the sum of the digits would be x + 2. Again, this would not result in a sum of 10, as x + 2 ≠ 10.
For y = 3, the sum of the digits would be x + 3. Similarly, x + 3 ≠ 10.
For y = 4, the sum of the digits would be x + 4. Once again, x + 4 ≠ 10.
For y = 5, the sum of the digits would be x + 5. And again, x + 5 ≠ 10.
For y = 6, the sum of the digits would be x + 6. Again, x + 6 ≠ 10.
For y = 7, the sum of the digits would be x + 7. x + 7 ≠ 10.
For y = 8, the sum of the digits would be x + 8. x + 8 ≠ 10.
This leaves us with only one possibility:
For y = 9, the sum of the digits would be x + 9. This should equal 10, so x + 9 = 10. Subtracting 9 from both sides, we find that x = 1. Therefore, if y = 9, the number will be 1.9.
Therefore, there are two possible numbers that meet the given criteria: 9.1 and 1.9.