what is the length of the diagonal of a rectangle 12m by 9m?
Pythagorean theorem again
12^2 + 9^2 = d^2
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem. The Pythagorean theorem states that the square of the hypotenuse (diagonal) of a right triangle is equal to the sum of the squares of the other two sides.
In this case, the length of the rectangle is 12m and the width is 9m. So, we can consider the length as one side of the right triangle and the width as the other side of the right triangle.
Using the Pythagorean theorem, we have:
Diagonal^2 = Length^2 + Width^2
Diagonal^2 = 12^2 + 9^2
Diagonal^2 = 144 + 81
Diagonal^2 = 225
Taking the square root of both sides, we get:
Diagonal = √225
Diagonal = 15m
Therefore, the length of the diagonal of the rectangle is 15 meters.
To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the length and width of the rectangle form the legs of a right triangle, and the diagonal acts as the hypotenuse. Let's call the length of the diagonal "d," the length of the rectangle "l," and the width of the rectangle "w."
So, we can use the Pythagorean theorem to solve for "d":
d² = l² + w²
Substituting the given values, we get:
d² = 12² + 9²
d² = 144 + 81
d² = 225
To find "d," we take the square root of both sides:
d = √225
d = 15
Therefore, the length of the diagonal of a rectangle with dimensions 12m by 9m is 15 meters.