A gun of mass 20 kg fires a bulllet of mass 50 g with a velocity of 200 ms. Calculate the velocity of the recoil of the gun

let,

bullets mass,m =5 gm = 0.05kg
bullet before shot velocity,u = 0m/s
bullets velocity,v= 200 m/s
guns mass,m'= 20kg
before shot,u'=0m/s
after shot velocity = v'
According to newton

mu+m'u' = mv+m'v'
now calculate, the velocity will be 0.5m/s

0.5 mper second

0.2

A force of 120 N acts on stationary body 4 second and the body required a velocity of 36ms . Calculate the mass of the body.

Well, calculating the velocity of the recoil of the gun is no shooting match! Let's give it a shot, shall we?

We'll use good old Newton's third law of motion here: for every action, there's an equal and opposite reaction. So, the momentum of the bullet is equal to the momentum of the gun.

The momentum of an object is given by the formula: momentum = mass × velocity.

The bullet has a mass of 50 g, which is 0.05 kg, and a velocity of 200 m/s. So, the momentum of the bullet is (0.05 kg) × (200 m/s) = 10 kg⋅m/s.

To find the velocity of the recoil of the gun, we have to consider that the gun's mass is 20 kg, and the total momentum is 10 kg⋅m/s. Since the bullet and the gun move in opposite directions, we can subtract the momentum of the bullet from the total momentum.

The momentum of the recoil is (20 kg) × (velocity of recoil). Equating that to the total momentum, we have: (20 kg) × (velocity of recoil) = 10 kg⋅m/s.

Let's solve for the velocity of recoil: velocity of recoil = 10 kg⋅m/s ÷ 20 kg = 0.5 m/s.

So, the velocity of the recoil of the gun is 0.5 m/s. Keep in mind that we don't want to burst anyone's bubble — this is just a hypothetical scenario for educational purposes. Stay safe!

To calculate the velocity of the recoil of the gun, we need to apply the principle of conservation of momentum. According to this principle, the total momentum before an event is equal to the total momentum after the event, provided no external forces are acting.

In this case, the total momentum before firing the bullet is zero since both the gun and the bullet are at rest. After firing, the total momentum should still be zero, but this time it will be divided between the gun and the bullet.

Let's assume the velocity of the gun after firing is v. The equation for conservation of momentum can be written as:

0 = (mass of gun) * (velocity of gun) + (mass of bullet) * (velocity of bullet)

Since the mass of the bullet is given in grams, let's convert it to kilograms by dividing by 1000:

0 = (20 kg) * v + (0.050 kg) * (200 m/s)

Simplifying the equation, we have:

0 = 20v + 10

Rearranging the equation to isolate v, we get:

20v = -10

Dividing both sides of the equation by 20, we find:

v = -0.5 m/s

Therefore, the velocity of the recoil of the gun is -0.5 m/s. The negative sign indicates that the gun moves in the opposite direction of the fired bullet.