Four more than twice Jason's age is the same as his age ten years from now. How old is Jason now?
if his age now is x, then
Four more than twice Jason's age is 2x+4
now do the other, set them equal, and find x.
To solve this problem, let's start by setting up an equation.
Let's assume Jason's age is x now.
Twice Jason's age is 2x, and four more than that is 2x + 4.
Jason's age ten years from now would be x + 10.
According to the problem, 2x + 4 is equal to x + 10.
Now we can solve for x:
2x + 4 = x + 10
To isolate x, we can subtract x from both sides:
2x - x + 4 = x - x + 10
Simplifying this equation gives us:
x + 4 = 10
To solve for x, we can subtract 4 from both sides:
x + 4 - 4 = 10 - 4
Simplifying further gives us:
x = 6
Therefore, Jason is currently 6 years old.