divide 95m long string such that twice of 1st part, 4 times of 2nd part and 5 times of 3rd part are equals
x+y+z = 95
2x = 4y
2x = 5z
50,25,20
To solve this problem, we need to divide a 95m long string into three parts such that twice the length of the first part, four times the length of the second part, and five times the length of the third part are equal.
Let's assume the length of the first part is x meters.
According to the problem statement, the length of the second part would be (2x)/4 = x/2 meters.
And the length of the third part would be (2x)/5 = 2x/5 meters.
Now, we can set up an equation to find the value of x:
x + x/2 + 2x/5 = 95
To solve for x, we need to first simplify the equation by finding a common denominator, which in this case is 10:
10x/10 + 5x/10 + 4x/10 = 95
Combining the terms on the left side of the equation, we have:
(10x + 5x + 4x) / 10 = 95
19x / 10 = 95
To isolate x, we can multiply both sides of the equation by 10/19:
(19x / 10) * (10 / 19) = 95 * (10 / 19)
x = 950 / 19
x ≈ 50
Now that we have found the value of x, we can determine the lengths of the three parts:
First part: x = 50 meters
Second part: x/2 = 50/2 = 25 meters
Third part: (2x)/5 = (2*50)/5 = 20 meters
So, the string can be divided into parts of length 50m, 25m, and 20m, respectively, in order to satisfy the given condition.