Sally bought 12 tickets for a movie, an adult ticket costs $9 and a child ticket costs $5, if she spent a total of $76, how many adults and children did she buy tickets for?

A = C + 4

9A + 5C = 76

Substitute C+4 for A in the second equation and solve for C. Insert that value into the first equation to solve for A. Check by putting both values into the second equation.

4 x$9.00=$36.00 8 x $5.00 =$40.00

To solve this problem, we can set up a system of equations representing the given information.

Let's assume that Sally bought "a" adult tickets and "c" child tickets.

According to the problem, she bought a total of 12 tickets, so we can write the first equation as:
a + c = 12

Additionally, we know the cost of an adult ticket is $9, and the cost of a child ticket is $5. The total amount Sally spent on tickets is $76, so we can write the second equation as:
9a + 5c = 76

Now we have a system of equations:
a + c = 12
9a + 5c = 76

To solve this system, we can use the substitution method or the elimination method. Let's use the elimination method:

Multiply the first equation by 5 to make the coefficients of "c" equal:
5(a + c) = 5(12)
5a + 5c = 60

Now we can subtract the second equation from this new equation to eliminate the variable "c":
(5a + 5c) - (9a + 5c) = 60 - 76
5a + 5c - 9a - 5c = -16
-4a = -16

Dividing both sides by -4 gives:
a = (-16) / (-4)
a = 4

Now we can substitute this value back into the first equation to solve for "c":
4 + c = 12
c = 12 - 4
c = 8

Therefore, Sally bought 4 adult tickets and 8 child tickets.