PLEASE HELP ME WITH THIS TRIGONOMETRY QUESTION!!?
Edit
Express each of the following in terms of another angle between 0 degrees and 180 degrees
a. sin 50 degrees
b. sin 150 degrees
c. cos 45 degrees
d. cos 120 degrees
Update: we have not yet learnt it in class i'm trying to analysis it but its not making senses, if you know how to solve it please show me the steps, i'm eager to learn!
recall that
sin(180-x) = sin(x)
cos(180-x) = -cos(x)
Using those two facts, you can replace each angle by its supplement.
Now, if you want to get fancy,
sin(90+x) = cos(x)
cos(90+x) = -sin(x)
As Reiny suggested, start by drawing triangles in the "standard position." goggle that if you don't understand the idea.
Certainly! I'd be happy to help you with the trigonometry question. To express each of the given angles in terms of another angle between 0 and 180 degrees, we can make use of the trigonometric identities.
a. To express sin 50 degrees in terms of another angle, we can use the identity sin(x) = sin(180 - x). In this case, we can see that 180 - 50 = 130 degrees. Therefore, sin 50 degrees can be expressed as sin 130 degrees.
b. Similarly, for sin 150 degrees, we can use the same identity sin(x) = sin(180 - x). In this case, 180 - 150 = 30 degrees. Therefore, sin 150 degrees can be expressed as sin 30 degrees.
c. For cos 45 degrees, we can use the identity cos(x) = sin(90 - x). In this case, 90 - 45 = 45 degrees. Therefore, cos 45 degrees can be expressed as sin 45 degrees.
d. Lastly, for cos 120 degrees, we can use the identity cos(x) = -cos(180 - x). In this case, 180 - 120 = 60 degrees. Therefore, cos 120 degrees can be expressed as -cos 60 degrees.
Now, let's express these angles in terms of another angle:
a. sin 50 degrees = sin 130 degrees
b. sin 150 degrees = sin 30 degrees
c. cos 45 degrees = sin 45 degrees
d. cos 120 degrees = -cos 60 degrees
I hope this helps! Let me know if you have any further questions or if there's anything else I can assist you with.