Evaluate the following expression given the function.

function: h(x)=12/x

problem: h(x) = -2
solution: -2 = 12/x.
1/12 * -2 = 12/x *1/12 (mulitply both sides by 1/12 to get x by itself.
-2/12 = 1/x
-1/6 = 1/x (simplified -2/12)

I don't think this is right. Can you explain how to get the 'x' out of the denominator?

don't be scared by that x. It's juts a denominator. To get rid of it, multiply both sides by x.

Now, to find x when h = -2, just do what you did:

12/x = -2
now just multiply by x:

12 = -2x
x = -6

Thanks! That was so much easier :).

To get 'x' out of the denominator, you can multiply both sides of the equation by 'x'. Here's the step-by-step process:

1. Start with the equation: -2 = 12/x
2. Multiply both sides of the equation by 'x': -2 * x = 12/x * x
3. Simplify the equation: -2x = 12
4. Divide both sides of the equation by -2 to isolate 'x': -2x / -2 = 12 / -2
5. Simplify the equation: x = -6

Therefore, the solution to the equation h(x) = -2 is x = -6.

To get the 'x' out of the denominator, you can start by multiplying both sides of the equation by 'x'. This allows you to cancel out the 'x' in the denominator on the right side of the equation.

So, starting from the equation:
-2/12 = 1/x,

Multiply both sides by 'x':
x * (-2/12) = x * (1/x).

On the left side, the 'x' cancels out with the denominator of '-2/12':
-2x/12 = 1.

Now, you can simplify the left side of the equation by dividing both the numerator and denominator by their greatest common divisor, which is 2 in this case:

-2x/2 * (1/12) = 1/2.
- x/6 = 1/2.

Now, the 'x' is no longer in the denominator. To solve for 'x', you can multiply both sides of the equation by 6 to isolate 'x':

- x/6 * 6 = 1/2 * 6.
- x = 3.

Therefore, the solution to the equation h(x) = -2, where h(x) = 12/x, is x = 3.