Rocket-powered sleds are been used to test the responses of humans to acceleration. Starting from rest, one sled can reach a speed of 495 m/s in 1.78 s and can be brought to a stop again in 2.16 s.

Find the acceleration of the sled while ac- celerating.
Answer in units of m/s2.

(part 2 of 2) 10.0 points
Find the acceleration of the sled when brak- ing.
Answer in units of m/s2.

To find the acceleration of the sled while accelerating, we can use the following equation:

acceleration = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = 0 m/s (starting from rest)
Final velocity (v) = 495 m/s
Time (t) = 1.78 s

Using the equation, we can calculate the acceleration:

acceleration = (495 m/s - 0 m/s) / 1.78 s
acceleration = 495 m/s / 1.78 s
acceleration ≈ 277.53 m/s²

Therefore, the acceleration of the sled while accelerating is approximately 277.53 m/s².

To find the acceleration of the sled while braking, we can again use the same equation:

acceleration = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = 495 m/s (speed of the sled before braking)
Final velocity (v) = 0 m/s (stopping the sled)
Time (t) = 2.16 s

Using the equation, we can calculate the acceleration:

acceleration = (0 m/s - 495 m/s) / 2.16 s
acceleration = -495 m/s / 2.16 s
acceleration ≈ -229.17 m/s²

Therefore, the acceleration of the sled while braking is approximately -229.17 m/s². The negative sign indicates that the sled is decelerating (slowing down).

To find the acceleration of the sled while accelerating, we can use the formula:

a = (v - u) / t

where:
a = acceleration
v = final velocity = 495 m/s
u = initial velocity = 0 m/s (starting from rest)
t = time taken to reach the final velocity = 1.78 s

Substituting the values into the formula:

a = (495 m/s - 0 m/s) / 1.78 s
a = 277.53 m/s / 1.78 s
a ≈ 155.86 m/s^2

Therefore, the acceleration of the sled while accelerating is approximately 155.86 m/s^2.

To find the acceleration of the sled when braking, we can use the same formula:

a = (v - u) / t

where:
a = acceleration
v = final velocity = 0 m/s (coming to a stop)
u = initial velocity = 495 m/s (from the previous step)
t = time taken to come to a stop = 2.16 s

Substituting the values into the formula:

a = (0 m/s - 495 m/s) / 2.16 s
a = -495 m/s / 2.16 s
a ≈ -229.17 m/s^2

Note: The negative sign indicates that the sled is decelerating (braking).

Therefore, the acceleration of the sled when braking is approximately -229.17 m/s^2.

a = change in velocity/change in time = 495/1.78 m/s^2

braking is opposite velocity
a = -495/2.16 m/s^2

note the acceleration of gravity is about 10 m/s^2 so this is more than 25 g,scary.