A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 ¡Á1000 kg meter cube. Calculate R.D. of solid.

Post answer

To find the relative density (R.D.) of a solid, we need to use the following formula:

R.D. = (Weight in air)/(Weight in air - Weight in liquid)

In this case, we are given the weight of the solid in air (1.5 kgf) and in the liquid (0.9 kgf), as well as the density of the liquid (1.2 × 1000 kg/m^3).

First, let's convert the weights from kgf to kg by dividing them by the acceleration due to gravity (g).

Weight in air = 1.5 kgf / 9.8 m/s^2 = 0.153 kg
Weight in liquid = 0.9 kgf / 9.8 m/s^2 = 0.092 kg

Now we can substitute these values into the formula:

R.D. = 0.153 kg / (0.153 kg - 0.092 kg)

R.D. = 0.153 kg / 0.061 kg

R.D. ≈ 2.51

Therefore, the relative density (R.D.) of the solid is approximately 2.51.

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