graph each equation

Y=5 (let x= -3,-2,-1,0,1,2,3)

Isn't this a straight line, horizontal, at y=5?

Yes but I don't understand why it's giving me the x values for

To graph the equation y = 5, you will plot points on a Cartesian plane where the y-value is always 5. Let's substitute different values of x to find the corresponding y-values:

When x = -3, y = 5
When x = -2, y = 5
When x = -1, y = 5
When x = 0, y = 5
When x = 1, y = 5
When x = 2, y = 5
When x = 3, y = 5

So, the set of ordered pairs is:
(-3, 5), (-2, 5), (-1, 5), (0, 5), (1, 5), (2, 5), (3, 5)

Now, let's plot these points on a graph:

.
.
.
.
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-----------------------------------------> x-axis
.
.
.
.
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(0, 5)

As you can see, all the points lie on the horizontal line at y = 5.

To graph the equation Y = 5, you will need to plot the points where x equals -3, -2, -1, 0, 1, 2, and 3, and set their corresponding y-values to 5.

Here's how you can do it step-by-step:

1. Create a coordinate grid or graph paper. Label the x-axis and y-axis.

2. Locate the point where x = -3. Go to the x-axis, find the point -3, and draw a vertical line from that point. Then go to the y-axis and locate the point where y = 5. Draw a horizontal line from that point. The point where the two lines intersect is (-3, 5).

3. Repeat the same process for each of the other given x-values (-2, -1, 0, 1, 2, 3). Draw a vertical line from each x-value point and a horizontal line from the corresponding y-value of 5.

4. Connect each of the points you plotted to form a straight line. Since all the y-values in this equation are 5, the line will be a horizontal line passing through all the x-values.

5. Finally, label the line you drew as Y = 5 to indicate that all the points on this line satisfy the equation.

The graph of the equation Y = 5 will be a horizontal line that passes through the points (-3, 5), (-2, 5), (-1, 5), (0, 5), (1, 5), (2, 5), and (3, 5).