a ball is vertically upward with a velocity of 35m/s. how long will the ball reaches the ground?
solve
35t - 4.9t^2 = 0
To find the time it takes for the ball to reach the ground, we need to use the equations of motion.
In this case, the ball is moving vertically upwards, so the acceleration due to gravity will act in the opposite direction, i.e., downwards. The acceleration due to gravity can be taken as approximately 9.8 m/s².
We can use the following equation of motion to solve for the time of flight:
v = u + at
Where:
v = final velocity (0 m/s, as the ball comes to rest at the highest point and then starts to fall down)
u = initial velocity (35 m/s)
a = acceleration (in this case, acceleration due to gravity, which is -9.8 m/s² as it is in the opposite direction)
t = time of flight (we need to find this)
Substituting the given values into the equation, we get:
0 = 35 - 9.8t
Rearranging the equation to isolate t, we have:
9.8t = 35
Dividing both sides by 9.8, we get:
t = 35 / 9.8
Using a calculator, we find :
t ≈ 3.57 seconds (rounded to two decimal places)
Therefore, it will take approximately 3.57 seconds for the ball to reach the ground.