If b= 11a, what is the average (arithmetic mean) of b and a in terms of a?
average = ( a + b ) / 2
substitute the value of b = 11a
( a + b ) / 2
( a + 11a ) / 2
= 12a / 2
= 6a
To find the average of two numbers, we add them together and divide by 2.
Given that b = 11a, we can substitute b in terms of a: b = 11a.
Now, to find the average of b and a, we add b and a together and divide by 2:
(a + b) / 2 = (a + 11a) / 2 = (12a) / 2 = 6a.
Therefore, the average (arithmetic mean) of b and a in terms of a is 6a.
To find the average (arithmetic mean) of two numbers, you add them together and divide the sum by 2. In this case, you want to find the average of b and a.
Since it is given that b = 11a, we can substitute this value in the formula for the average.
Average = (b + a) / 2 = (11a + a) / 2 = 12a / 2 = 6a
Therefore, the average of b and a in terms of a is 6a.