Is it possible to have a regular polygon each of whose exterior angles is 50
If exterior angle is 50°, then each interior angle is 130°
let the number of sides be n , where n is a whole number
sum of interior angles = 180(n-2)
each interior angle is 180(n-2)/n
180(n-2)/n = 130
180n - 360 = 130n
50n = 360
n = 7.2 , silly answer, so
nope, not possible
Payal mittal , ayush mittal , Vivek mittal , vabivam mittal , ayushi mittal Geeta mittal , naresh mittal
Is it possible to have a regular polygon each of whose exterior angles is 50degree
To determine whether it is possible to have a regular polygon with each of its exterior angles measuring 50 degrees, we need to use the formula for the measure of an exterior angle of a regular polygon.
The formula to calculate the measure of each exterior angle of a regular polygon is:
exterior angle = 360 degrees / number of sides
Let's apply this formula to the situation at hand. Since we want each exterior angle to measure 50 degrees, we can set up an equation:
50 degrees = 360 degrees / number of sides
Now, we can solve for the number of sides:
Number of sides = 360 degrees / 50 degrees
Number of sides = 7.2
The result is 7.2, which implies that the number of sides of the regular polygon is not a whole number. However, a regular polygon must have a whole number of sides. Therefore, it is not possible to have a regular polygon with each of its exterior angles measuring 50 degrees.