2.00g of carbonate reacts with excess hydrobromic acid. Use this balanced equation to fond the theoretical yield.

Na2Co3 + 2HBr = CO2 + H2O + 2NaBr

To find the theoretical yield, we need to use the balanced equation and the given mass of the reactant (carbonate) to calculate the moles of reactant, and then use stoichiometry to determine the moles of the product (CO2). Finally, we can convert the moles of CO2 into grams using its molar mass.

Let's calculate step by step:

1. Calculate the moles of the given reactant (carbonate):
To do this, we need the molar mass of Na2CO3, which is 106 g/mol.

Moles of Na2CO3 = mass / molar mass
Moles of Na2CO3 = 2.00 g / 106 g/mol
Moles of Na2CO3 = 0.0189 mol

2. Use stoichiometry to find the moles of CO2 produced:
From the balanced equation, we can see that 1 mole of Na2CO3 produces 1 mole of CO2.
So, the moles of CO2 produced will also be 0.0189 mol.

3. Convert the moles of CO2 into grams:
Now, we need the molar mass of CO2, which is 44 g/mol.

Mass of CO2 = moles of CO2 × molar mass
Mass of CO2 = 0.0189 mol × 44 g/mol
Mass of CO2 = 0.8316 g

Therefore, the theoretical yield of CO2 is 0.8316 grams.