Distance travelled by a ball dropped from a cliff in the 10th second.
v = g t = 9.81 t
at t = 9, v = 9.81 * 9
at t = 10, v = 9.81 * 10
average speed during tenth second 4.9 (19)
distance during tenth
= 4.9 * 19 * 1
a ball is dropped from calif. find its distance covered in 6th second
To determine the distance traveled by a ball dropped from a cliff in the 10th second, we need to consider the formula for distance traveled due to gravity.
The formula for the distance traveled by an object in free fall is:
d = 1/2 * g * t^2
Where:
d = distance traveled
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time
In this case, we want to find the distance traveled in the 10th second, so we substitute t = 10 into the formula:
d = 1/2 * g * (10^2)
Now let's plug in the values and calculate the answer:
d = 1/2 * 9.8 * (10^2)
d = 1/2 * 9.8 * 100
d = 4.9 * 100
d = 490 meters
Therefore, the ball would have traveled 490 meters in the 10th second when dropped from a cliff.