" I am thinking of a number thrice my number minus 6 equals 66"

3x-6 = 66

Ah, the old number riddle! Let's tackle it together. So, we know that thrice the number minus 6 equals 66. Well, let me just say, that's a rather complex way of making math interesting! Alright, let's dive in.

We can represent the unknown number as 'x'. According to the riddle, 3 times 'x' minus 6 should equal 66. So, let's set up the equation: 3x - 6 = 66. Now, I'd love to give you the answer right away, but I'm just a clown bot, not a math wizard.

But fret not! We can solve this together! All we have to do is add 6 to both sides of the equation, and we get 3x = 72. Now, divide both sides by 3, and voila! We find that x equals 24.

So, the number you were thinking of is 24! But hey, don't keep those numbers all to yourself. Share them with your friends, and let them marvel at your mathematical prowess!

To solve the equation, let's represent the unknown number as "x".

The given equation is: "Thrice my number minus 6 equals 66".

So we can write it as an equation:

3x - 6 = 66

To isolate the variable x, we need to get rid of the constant term (-6) by adding 6 to both sides of the equation:

3x - 6 + 6 = 66 + 6

This simplifies to:

3x = 72

Now, to solve for x, we can divide both sides of the equation by 3:

3x / 3 = 72 / 3

This gives us:

x = 24

Therefore, the number you are thinking of is 24.

To solve this problem, you need to set up an equation based on the given information and then solve for the unknown number. Let's go step by step:

1. Let's assume your number is represented by the variable x.
2. "Thrice my number" can be written as 3x.
3. "Minus 6" can be written as -6.
4. "Equals 66" can be written as = 66.

Putting it all together, the equation becomes: 3x - 6 = 66.

Now, we need to solve for x:

1. Start by adding 6 to both sides of the equation to isolate the term with x:
3x - 6 + 6 = 66 + 6
3x = 72

2. Next, divide both sides of the equation by 3 to solve for x:
3x/3 = 72/3
x = 24

So, the number you were thinking of is 24.