Calculate the pH of the solution 5ml of M/5,HCl+10ml of M/10 NaO
To calculate the pH of a solution, we need to determine the concentration of the hydronium ions (H3O+) in the solution.
First, let's determine the moles of HCl and NaOH used:
Molarity (M) = Moles (mol) / Volume (L)
For HCl:
M/5 = Moles HCl / 0.005 L (5 mL)
Moles HCl = (M/5) * 0.005 L
For NaOH:
M/10 = Moles NaOH / 0.010 L (10 mL)
Moles NaOH = (M/10) * 0.010 L
Next, let's determine the total volume of the solution:
Volume (total) = Volume HCl + Volume NaOH
Volume (total) = 0.005 L + 0.010 L
Now, let's calculate the moles of hydronium ions formed by the reaction between HCl and NaOH:
HCl + NaOH → H2O + NaCl
Since this is a 1:1 stoichiometric reaction, the moles of HCl reacted will be equal to the moles of hydronium ions formed.
Moles H3O+ = Moles HCl
Finally, let's determine the concentration of hydronium ions in the solution:
Concentration (H3O+) = Moles H3O+ / Volume (total)
pH is defined as the negative logarithm (base 10) of the hydronium ion concentration:
pH = -log[H3O+]
Now, you have all the necessary information to calculate the pH of the solution. Plug in the values into the formulas mentioned, and you will get the final answer.