a 20 kg crate is at rest on level ground a worker begins pushing horizontally on the crate with a force 300 Newtons, but the crate does not move determine the weight of the crate in both units of newtons and units of and units of pounds, determine the normal force acting on the crate in both units in units of newtons. If static friction is the only thing preventing the crate from moving determine the coefficient of static friction and explain whether or not this coefficient is valid.

weight=mass*g

= 20*9.8

mu=300/weight
mu=300/196

yes it is valid. The crate could be stuck in sticky paste

To determine the weight of the crate in both units of newtons and pounds, we can use the equation:

Weight = mass x gravity

Given that the mass of the crate is 20 kg, and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the weight:

Weight (in newtons) = 20 kg x 9.8 m/s^2 = 196 N

To convert the weight from newtons to pounds, we can use the conversion factor: 1 N = 0.2248 lbs

Weight (in pounds) = 196 N x 0.2248 lbs/N ≈ 44.06 lbs

Now, let's determine the normal force acting on the crate. The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the crate is at rest on level ground, so the normal force is equal in magnitude and opposite in direction to the weight of the crate.

Therefore, the normal force acting on the crate is also 196 N (upwards).

Next, if the crate is not moving, it means that the static friction force is equal in magnitude and opposite in direction to the applied force. We can use the equation:

Fs (maximum static friction) = coefficient of static friction x normal force

Since the crate is not moving, the applied force of 300 N is equal to the maximum static friction force:

300 N = coefficient of static friction x 196 N

Solving for the coefficient of static friction:

coefficient of static friction = 300 N / 196 N
coefficient of static friction ≈ 1.53

Now, it's important to determine whether this coefficient is valid. Generally, the coefficient of static friction ranges between 0 and 1, representing the friction relationship between two surfaces. However, in this case, the calculated coefficient of static friction is greater than 1 (1.53), which is unusual and indicates that something might be incorrect with the calculations or assumptions made.

Therefore, this coefficient of static friction may not be valid, and further investigation or checking of the calculations should be done to determine the correct value.