Predict the heat output of the combustion of 1L of octane at 298K. It's mass density is.703 g/cm3
To predict the heat output of the combustion of 1L of octane at 298K, you would need to know the heat of combustion of octane. The heat of combustion is the amount of heat released when a substance undergoes complete combustion.
Here's how you can calculate the heat output using the heat of combustion:
1. Determine the mass of octane: To convert liters to grams, you need to know the density of octane. Given that the mass density of octane is 0.703 g/cm3, and you have 1L of octane, you can calculate the mass as follows:
Mass = Volume x Density
Since the volume is given in liters and the density is given in g/cm3, you need to convert the volume to cm3:
1L = 1000 cm3
Substituting the values:
Mass = 1000 cm3 x 0.703 g/cm3 = 703 g
2. Find the molar mass of octane: Octane has a molecular formula of C8H18. To calculate the molar mass, you need to add up the atomic masses of each element. Looking up the periodic table, you can find that the atomic masses are approximately 12.01 g/mol for carbon (C) and 1.01 g/mol for hydrogen (H).
Molar mass of octane = (8 x 12.01 g/mol) + (18 x 1.01 g/mol) = 114.23 g/mol
3. Calculate the heat output: The heat of combustion of octane (ΔH) is typically given in units of energy per mole (e.g., kJ/mol or J/mol). Let's assume the heat of combustion for octane is -5471 kJ/mol (-5471000 J/mol).
To calculate the heat output, you can use the formula:
Heat output = (Mass of octane / Molar mass of octane) x Heat of combustion
Substituting the values:
Heat output = (703 g / 114.23 g/mol) x (-5471000 J/mol)
Calculating this value will give you the predicted heat output of the combustion of 1L of octane at 298K.