a tank was 10 percent full and contained 30l of water what is the full capacity of the tank
please dear lectures it is not my homework i am poor in math and tommorow is my test if i could please get the work now
10percent=30litres
100percent=x
x=(100*30)/10=30litres
Efa started out right, but then lost track of the math.
100% is 10 times 10%
So, the full tank is 10 times 30L = 300L
To find the full capacity of the tank, we can use the concept of percentages and proportions.
Given that the tank is currently 10 percent full and contains 30 liters of water, we can assume that when the tank is 100 percent full, it will contain some unknown amount of water (let's call it "x" liters).
To set up the proportion, we can say:
10% (current level) is to 30 liters (current amount) as 100% (full capacity) is to x liters (unknown amount).
Mathematically, we can express this as:
10/100 = 30/x
To solve for x, we can cross-multiply and then solve for x:
10x = 100 * 30
10x = 3000
x = 3000/10
x = 300
Therefore, the full capacity of the tank is 300 liters.