A bag contains 8 red; marbles, 2 blue; marbles, and 1 green marble. What is the probability that a randomly selected marble is not blue?
Well, if you don't want a blue marble, that leaves us with the red and green marbles. There are a total of 11 marbles in the bag, so the probability of not picking a blue marble would be 11 minus the 2 blue marbles, divided by the total number of marbles. So, the answer is 9 out of 11. Just remember, blue is feeling a little left out in this question!
To find the probability that a randomly selected marble is not blue, we need to determine the total number of marbles and the number of non-blue marbles.
Total number of marbles = 8 (red) + 2 (blue) + 1 (green) = 11
Number of non-blue marbles = 8 (red) + 1 (green) = 9
Therefore, the probability that a randomly selected marble is not blue is 9/11.
To find the probability that a randomly selected marble is not blue, we first need to determine the total number of marbles in the bag that are not blue.
In this case, the bag contains 8 red marbles, 2 blue marbles, and 1 green marble, meaning there are a total of 8 + 2 + 1 = 11 marbles.
Next, we need to determine the number of marbles that are not blue, which is the sum of the red and green marbles. Therefore, there are 8 + 1 = 9 marbles that are not blue.
Finally, we can calculate the probability by dividing the number of marbles that are not blue by the total number of marbles:
Probability = Number of marbles not blue / Total number of marbles = 9 / 11.
So, the probability that a randomly selected marble is not blue is 9/11 or approximately 0.8182 (rounded to four decimal places).