Moss and Roy both decide to go out for a 2 course dinner. Moss' meal cost twice as much as Roy's meal, however Roy spent $3 more than Moss for his dessert. Moss spent $11 on his desert. The bill came to $75. How much did Roy spend for his meal and dessert?
M = 2R
M + 11 + R + 11 + 3 = 75
Roy's dessert ... 11 + 3 = $14
3R + 25 = 75 ... R = 50/3
Roy's meal ... $50/3
So the answer is $41
Answer is $16.5
Let's assume that the cost of Roy's meal is X dollars.
According to the information given, Moss' meal cost twice as much as Roy's meal. Therefore, Moss' meal would cost 2X dollars.
Additionally, it is mentioned that Roy spent $3 more than Moss on dessert. We know that Moss spent $11 on dessert. Therefore, Roy spent 11 + 3 = $14 on dessert.
To calculate the total bill, we add the cost of Moss' meal, Roy's meal, Moss' dessert, and Roy's dessert:
Total bill = Moss' meal + Roy's meal + Moss' dessert + Roy's dessert
Total bill = 2X + X + 11 + 14
Given that the total bill came to $75, we can set up the equation:
75 = 3X + 25
Subtracting 25 from both sides of the equation:
50 = 3X
Dividing both sides of the equation by 3:
X = 16.67 (rounded to two decimal places)
Therefore, Roy spent approximately $16.67 for his meal and $14 for his dessert.