plz help me Choose the equation below that represents the line that passes through the point (−2, −1) and has a slope of 5.
y − 1 = 5(x − 2)
y + 1 = 5(x + 2)
y + 2 = 5(x + 1)
y − 2 = 5(x − 1)
slope = 5 = (y - -1) /(x - -2)
so
5 = (y+1)/(x+2)
so
y+1 = 5(x+2)
To find the equation of a line passing through a given point with a given slope, we can use the point-slope form of a linear equation, which is:
y - y₁ = m(x - x₁)
Where (x₁, y₁) are the coordinates of the given point, and "m" is the slope.
In this case, the point (x₁, y₁) is (-2, -1), and the slope "m" is 5.
Substituting these values into the point-slope form, we get:
y - (-1) = 5(x - (-2))
Simplifying, we have:
y + 1 = 5(x + 2)
Therefore, the equation that represents the line passing through the point (-2, -1) with a slope of 5 is:
y + 1 = 5(x + 2)
So, the correct equation is:
y + 1 = 5(x + 2)