Create an image of a dynamic physics experiment in progress. The central object is a spiral spring, in a state of compression, having been pushed down by 0.04 meters. The spring's metallic coils are tightly wound, showcasing the force being applied to it. Quantifiable elements such as force and energy have been made visible as abstract shapes, representing the 400N/m force constant applied to the spring. However, no numerical measures or text should be present in the image. The overall image should be vivid and appealing, aiming to stimulate curiosity in the viewer about the principles of physics.

A spiral spring is compressed by 0.04m. Calculate the energy stored in the spring if the force constant is 400N/m... pls I need help wif dis, detailed answers pls, tnx

Well, well, well, it seems you have a springy question for me! Don't worry, I'm here to help you bounce back with a big grin.

To calculate the energy stored in a compressed spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. In equation form, it's F = -kx, where F represents force, k is the force constant, and x is the displacement.

Now, to determine the energy stored in the spring, we need to integrate the force function with respect to displacement. The integral of force with respect to displacement gives us the potential energy stored in the spring.

So, let's crunch some numbers. In this case, we have a force constant, k, of 400 N/m and a displacement, x, of 0.04 m.

The potential energy stored in the spring (U) can be calculated using the formula:

U = (1/2)kx²

Substituting the given values, we get:

U = (1/2) * (400 N/m) * (0.04 m)²

Now, let's do some math magic:

U = (1/2) * (400 N/m) * (0.04 m * 0.04 m)
U = (1/2) * (400 N/m) * (0.0016 m²)
U = (1/2) * (0.64 Nm)
U = 0.32 Nm

And there you have it! The energy stored in the compressed spring is 0.32 Nm (or Joules if you prefer).

Keep that springy spirit!

1/2×800×0.04^2

1/2×800×0.0016
400×0.0016
0.64

stored potential energy = (1/2)k x^2

= (1/2)(400)(.04)^2

I need full calculation

A spiral spring is compressed by 0.04m .calculate the energy stored in the spring ,if the force constant is 800n/m

To calculate the energy stored in a spring, we will use the formula for elastic potential energy, which is given by:

E = (1/2) * k * x^2

where:
E = energy stored in the spring (in joules),
k = force constant of the spring (in Newtons/meter),
x = displacement of the spring from its equilibrium position (in meters).

In this case, the force constant (k) is given as 400 N/m, and the spring is compressed by 0.04m (x = 0.04m).

Substituting these values into the formula, we get:

E = (1/2) * 400 N/m * (0.04m)^2

Let's calculate it step by step:

First, square the value of x:
(0.04m)^2 = 0.0016 m^2

Then, multiply the force constant (k) by the squared displacement (x^2):
400 N/m * 0.0016 m^2 = 0.64 J

Therefore, the energy stored in the spring is 0.64 joules.