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does an=(-1)^n converge? Explain
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of course not. List a few terms.
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formalize the following statment: a_n is a sequence that doesnt converge to L∈R. prove that the sequance (1/n) does not
Top answer:
To formalize the statement "a_n is a sequence that doesn't converge to L ∈ R," we can use
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The sum from n=1 to infinity of cos(npi/3)/n!
Does this absolutely converge, conditionally converge, or diverge?
Top answer:
Group every 6 terms (1 cycle) together and consider as an aggregate term for a new series, ΣQn.
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What does the following infinite series starting at k=2 converge to: Σ ln (1 - 1/k^2)
In other words, what does this converge
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The kth factor in the product is: 1-1/k^2 = (k^2-1)/k^2 = (k+1)(k-1)/k^2 We can write this as:
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n=1 series to infinity (-5^n)/n^3 does it absolutely converge, diverge or conditionally converge. Would I be applying the ratio
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Sorry it's *(-5)^n and I don't think its absolutely convergent, am I correct?
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How would I do this one?
n=1 to infinity n^n/4^1+3*n Does it absolutely converge, conditionally converge, or diverge? What would
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n^n /[ 4^(1+3n) ] or what? Need parentheses to see what you mean. By the way that clearly does not
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Which of the following statements about language is true?
A. Languages can diverge and converge. B. Languages can diverge but not
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A. Languages can diverge and converge.
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How would you find converge or diverges of an=5/n+2
This is what I did Limit n--->∞ 5/∞+2=5/∞=0 So does it converge
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it does converge to zero. You can't formally use ∞ as a value. You need to show that for
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does the sequence a=(2n)! / n! converge? Explain
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A necessary condition for convergence is that the limit Lim an =0 n->∞ Can you evaluate the limit
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Does the series converge?
Explain please 1/(ln 2)^n from n=1 to infinity
Top answer:
since ln2 < 1 1/ln2 > 1 so it diverges
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For the sequences below, find if they converge or diverge. If they converge, find the limit.
an=(3^(n+2))/(5^n) an=cos(2/n)
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1) (3^(n+2))/(5^n) = 3^2 (3/5)^n This converges to zero. 2) cos(2/n) converges to cos(0) = 1 3)
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∑∞n=1−4(−12)n−1
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For what values of k does the series ∑n=1 to infinity (11/(2k^2 + 3))^n converge?
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Where does this infinite series converge:
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Does the series ln/n^2 converge using the L'Hoptial's rule also.
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Does the infinite geometric series diverge or converge? Explain
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