Sn=3n-2.Find the 1st,3rd and 5th term
just plug in
n = 1, n = 3, n = 5
If will do the n = 3
S(n) = 3(3) - 2 = 7
1st term:
n = 1
Sn = 3 n - 2
S1 = 3 * 1 - 2 = 3 - 2 = 1
3rd term:
n = 3
Sn = 3 n - 2
S3 = 3 * 3 - 2 = 9 - 2 = 7
5th term:
n = 5
Sn = 3 n - 2
S5 = 3 * 5 - 2 = 15 - 2 = 13
To find the 1st, 3rd, and 5th terms of the given sequence Sn=3n-2, we need to substitute the values of n into the equation.
1st term: We substitute n = 1 into the equation Sn = 3n - 2:
S1 = 3(1) - 2 = 3 - 2 = 1
3rd term: We substitute n = 3 into the equation Sn = 3n - 2:
S3 = 3(3) - 2 = 9 - 2 = 7
5th term: We substitute n = 5 into the equation Sn = 3n - 2:
S5 = 3(5) - 2 = 15 - 2 = 13
Therefore, the 1st, 3rd, and 5th terms of the sequence Sn = 3n - 2 are 1, 7, and 13, respectively.