You discover a new cell type that contains measurable amounts of silver ions (Ag+) in it. You find that the concentration of Ag+ inside the cell is still 10 times lower than the concentration outside. Calculate the amount of membrane potential that results from this amount of silver. Use the simplified form of the Nerst equation, V = 62 log (Co/Ci)
Thank you!
v=62 log(10)=62 millivolts?
To calculate the membrane potential resulting from the concentration of silver ions (Ag+) inside and outside the cell, we can use the simplified form of the Nernst equation:
V = 62 log (Co/Ci)
Where:
V = Membrane potential (in millivolts)
Co = Concentration of silver ions outside the cell (in mol/L)
Ci = Concentration of silver ions inside the cell (in mol/L)
In this case, we are given that the concentration of Ag+ inside the cell is 10 times lower than the concentration outside. Therefore, we can say:
Ci = (1/10) * Co
Substituting this into the simplified Nernst equation, we get:
V = 62 log (Co / ((1/10) * Co))
Simplifying further:
V = 62 log (10)
Now, we can use the logarithmic property log(a) = b to simplify the equation:
10^b = 10
Therefore:
V = 62
So, the amount of membrane potential resulting from this concentration of silver ions is 62 millivolts.