How fast would a 20gram marble have to go to travel 9.5 inches. (Flat surface)
To determine the speed at which a 20-gram marble would need to travel to cover a distance of 9.5 inches on a flat surface, we can use basic physics equations. The equation that relates speed (v), distance (d), and time (t) is:
v = d / t
First, let's convert the distance from inches to meters, as the SI unit for speed is meters per second. Since 1 inch is equal to 0.0254 meters, the distance of 9.5 inches is:
d = 9.5 inches * 0.0254 meters/inch = 0.2413 meters
Next, we need to determine the time it takes for the marble to cover this distance. However, we don't have enough information to directly calculate the time. The time (t) can be determined by dividing the distance by the speed (t = d / v). Therefore, we need to rearrange the equation to solve for speed:
v = d / t --> t = d / v
Since we don't have the time or speed, we cannot directly calculate the speed required. However, we can determine the average speed by assuming a time frame to travel the given distance. Let's assume the marble takes 1 second to travel the 9.5 inches:
t = 1 second
We can now calculate the average speed:
v = d / t = 0.2413 meters / 1 second ≈ 0.2413 meters per second
Therefore, to travel a distance of 9.5 inches on a flat surface, the 20-gram marble would need to have an average speed of approximately 0.2413 meters per second.