A typical antacid contains CaCO3. If such an antacid is added to 25.0 mL of a solution that is 0.250 M in HCl, how many grams of CO2 gas are produced?
First, set up the balanced equation.
.025L of .25M HCl has .00625 moles HCl.
Now just see how many moles of CO2 are produce for each mole of HCl.
Convert the result to grams.
To find the number of grams of CO2 gas produced, we first need to understand the chemical reaction that occurs between CaCO3 and HCl. The balanced chemical equation is:
CaCO3 + 2 HCl -> CaCl2 + CO2 + H2O
From the balanced equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2.
To find the number of moles of CaCO3, we need to use the concentration of HCl and the volume of the solution it reacts with.
First, convert the volume of the HCl solution from milliliters to liters:
25.0 mL = 25.0 mL * (1 L / 1000 mL) = 0.025 L
Now, use the formula C1V1 = C2V2 to find the number of moles of HCl:
(0.250 M) * (0.025 L) = 0.00625 moles of HCl
Because the ratio of CaCO3 to HCl is 1:2, the number of moles of CaCO3 is half of the number of moles of HCl:
0.00625 moles HCl * (1 mole CaCO3 / 2 moles HCl) = 0.003125 moles CaCO3
Since we know that 1 mole of CaCO3 produces 1 mole of CO2, the number of moles of CO2 produced is also 0.003125 moles.
Finally, to find the mass of CO2 gas produced, we need to use the molar mass of CO2:
Molar mass of CO2 = 12.01 g/mol (C) + 16.00 g/mol (O) + 16.00 g/mol (O) = 44.01 g/mol
Mass of CO2 gas produced = Number of moles of CO2 * Molar mass of CO2:
0.003125 moles CO2 * 44.01 g/mol = 0.138 g of CO2
Therefore, approximately 0.138 grams of CO2 gas are produced.