A big can contains some milk pots of 2 liters, 4 liters, 5 liters capacity are to be filled whole number of time from each. What can be the least capacity of the big can.

Answer=20

I thing so this answer is 11

To find the least capacity of the big can, we need to find the smallest common multiple of 2, 4, and 5 liters. The smallest common multiple is the smallest positive integer that is divisible by each of the given numbers.

We can find the least common multiple (LCM) of several numbers by prime factorization.

Step 1: Prime factorize each of the given numbers.
- Prime factorization of 2: 2^1
- Prime factorization of 4: 2^2
- Prime factorization of 5: 5^1

Step 2: Take the highest power of each prime factor.
- The highest power of 2 is 2^2 = 4
- The highest power of 5 is 5^1 = 5

Step 3: Multiply the highest powers of each prime factor.
4 * 5 = 20

Therefore, the least capacity of the big can must be 20 liters in order to accommodate pots of 2 liters, 4 liters, and 5 liters capacity for a whole number of times.

2 + 4 + 5 = 11

The answer is 11

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