Write an equation for a log functions base 2 whose graph has the following properties:
vertical asymptote of x=-6
Domain of x<-6
Passing through (-8,3)
log_2(x) has asymptote at x=0, so
log_2(x+6) has its asymptote at x=-6
But, its domain is x > -6. So, we want
log_2(-x-6)
at x = -8, we have
log_2(8-6) = 1
So, we want
y = 3log_2(-x-6)