1, A Body Of Mass 6kg Was Acted Upon By A Constant Force Of 18N. Calc Its Velocity In 5sec. 2. A Car Moving At 108km/hr Was Gradually Brought To Rest By Constant Force Of 2500N After 8sec. Calc The Decelleratio

F = ma, so a = F/m = 18N/6kg = 3 m/s^2

v = at = 3*5

Now you try the other. Same ideas.

To answer the first question, we need to use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. The formula for acceleration is given by:

a = F/m

where a is the acceleration, F is the force, and m is the mass.

In this scenario, we are given the mass of the body (6 kg) and the force applied (18 N). From the formula above, we can calculate the acceleration:

a = F/m
a = 18 N / 6 kg
a = 3 m/s²

Once we have the acceleration, we can use the kinematic equation relating accelerated motion to calculate the velocity of the body.

The formula is:

v = u + at

where v is the final velocity, u is the initial velocity (which is 0 in this case since the body starts from rest), a is the acceleration, and t is the time.

In this scenario, the initial velocity is 0 m/s and the time is 5 seconds. Plugging these values into the formula:

v = 0 + (3 m/s²) * 5 s
v = 15 m/s

Therefore, the velocity of the body after 5 seconds is 15 m/s.

For the second question, we are given the initial velocity of the car (108 km/hr), the force applied to bring it to a stop (2500 N), and the time it takes to come to a rest (8 seconds).

To calculate the deceleration, we can once again use Newton's second law of motion. However, this time we need to rearrange the formula to solve for acceleration:

a = F/m

In this case, the force is given as 2500 N, but the mass is not provided. Therefore, we need to use another formula to calculate the mass:

Force = mass * acceleration

Rearranging the formula gives us:

mass = Force / acceleration

Plugging in the values we have:

mass = 2500 N / acceleration

Now we can use the formula for acceleration:

a = F / m

a = 2500 N / (2500 N / acceleration)
a = 1 / (2500 N / 2500 N/s²)
a = 1 s²

Therefore, the deceleration of the car is 1 m/s².

It's important to note that deceleration is just negative acceleration, indicating that the car is slowing down. So the magnitude of the deceleration is 1 m/s².