If a solid state lithium battery produced 5.00 mA in 8.25 h, then the mass, in milligrams, of lithium consumed would be?

This is done the same way as the Cu post I did for you above.

To find the mass of lithium consumed, we need to use the equation:

Mass of lithium consumed = Current × Time

Given that the current is 5.00 mA (milliamperes) and the time is 8.25 hours, we can plug these values into the equation to calculate the mass.

First, let's convert the current from milliamperes to amperes:

1 mA = 0.001 A

Therefore, the current in amperes is:

5.00 mA × 0.001 A/mA = 0.005 A

Now we can calculate the mass of lithium consumed:

Mass of lithium consumed = 0.005 A × 8.25 h

Next, convert hours to seconds:

1 h = 3600 s

Therefore, the time in seconds is:

8.25 h × 3600 s/h = 29700 s

Now we can calculate the mass:

Mass of lithium consumed = 0.005 A × 29700 s

Finally, we need to convert the mass to milligrams. Since 1 gram (g) equals 1000 milligrams (mg), we can convert from grams to milligrams as follows:

1 g = 1000 mg

Therefore, the mass in milligrams is:

Mass of lithium consumed = (0.005 A × 29700 s) × 1000 mg/g

By calculating this expression, we will find the mass of lithium consumed in milligrams.