Calculate number of electrons present in 9.5g of PO4^3-

5NA

5 NA

5 Na

To calculate the number of electrons present in a given substance, you need to know the molar mass of the substance and Avogadro's number. Here's how you can get the answer:

Step 1: Find the molar mass of PO4^3-
The molecular formula for phosphate ion (PO4^3-) consists of one phosphorus atom and four oxygen atoms. You can find the atomic masses of each element from the periodic table:

Molar mass of phosphorus (P) = 31 g/mol
Molar mass of oxygen (O) = 16 g/mol

So, the molar mass of PO4^3- can be calculated as follows:
Molar mass of PO4^3- = (1 × molar mass of phosphorus) + (4 × molar mass of oxygen)
= (1 × 31 g/mol) + (4 × 16 g/mol)
= 31 g/mol + 64 g/mol
= 95 g/mol

Step 2: Calculate the number of moles of PO4^3-
To find the number of moles, divide the given mass by the molar mass:
Number of moles = Mass / Molar mass
= 9.5 g / 95 g/mol
= 0.1 mol

Step 3: Calculate the number of ions present
Since one formula unit of PO4^3- contains three ions (3- charge), you can calculate the number of ions as follows:
Number of ions = Number of moles × Avogadro's number × Charge
= 0.1 mol × 6.022 × 10^23 mol^-1 × 3
= 1.8066 × 10^23 ions

Step 4: Calculate the number of electrons
Each phosphate ion (PO4^3-) contains one extra electron, which is gained through the negative charge. Therefore, the number of electrons is the same as the number of ions:
Number of electrons = Number of ions
= 1.8066 × 10^23 electrons

So, there are approximately 1.8066 × 10^23 electrons in 9.5 grams of PO4^3-.

5Na

5x 6. 023E23

mols PO4^3- ion = grams/molar mass = 9.5/approx 95 = approx 0.1 but you need to confirm all of that.

There are 6.02E23 PO4^3- ions in 1 mol; therefore, there are 6.02E22 mols in the 9.5 g.
In 1 PO4^3- there are 31 electrons in the P atom and 4*8 = 32 electrons in the 4 O atoms. 31 + 32 = 63 total electrons in each PO4^3- ion. So in 6.02E22 ions there will be ......... electrons.