Adora has a photo of the Calgary tower that measures 7cm by 19cm. She scans the photo and enlarges it by 160%. By what percentage will the area of the photo increase?
A.) 160%
B.) 320%
C.) 410%
D.) 256%
A shop sells a small globe that hangs on a keychain, a medium globe used as a paperweights and a large globe for use in the classroom. The volume of the medium globe is six times the volume of the small globe and the volume of the large globe is nine times the volume of the small globe. Determine the scale factor relating the dimensions of the small and medium globes.
A.) k=6^3
B.) k=root 6
C.) k=6
D.) k=^3root6
A gift shop in Cairo sells a tiny pyramid pendant. Due to its popularity,the shop decided to make two larger, yet similar versions: medium(double the volume of the tiny one) and large(triple the volume of the tiny one). What is the factor relating the surface area of the tiny pyramid to the surface area of the medium pyramid? (the pyramids dimensions are 1 cm by 1 cm by 1 cm).
A.) 4
B.) ^3root4
C.) ^6root2
D.) 8
To find the percentage increase in the area of the photo, we first need to calculate the original area and the new area after the enlargement.
Original area = length x width = 7cm x 19cm = 133cm²
After enlarging by 160%, the new dimensions can be calculated by multiplying each dimension by 1 + (160% / 100%) = 2.6.
New length = 7cm x 2.6 = 18.2cm
New width = 19cm x 2.6 = 49.4cm
New area = new length x new width = 18.2cm x 49.4cm = 898.28cm²
Now let's compare the new area to the original area to determine the percentage increase:
Percentage increase = ((new area - original area) / original area) x 100%
= ((898.28cm² - 133cm²) / 133cm²) x 100%
= (765.28cm² / 133cm²) x 100%
≈ 576.18%
Therefore, the area of the photo will increase by approximately 576.18%, which is not one of the options given. None of the answer choices provided is correct.
To find the increase in the area of the photo, we need to find the ratio of the new area to the original area.
The original area of the photo is 7 cm * 19 cm = 133 cm^2.
After enlarging the photo by 160%, the new dimensions are 7 cm * 1.6 = 11.2 cm (rounded to one decimal place) and 19 cm * 1.6 = 30.4 cm (rounded to one decimal place).
The new area of the photo is 11.2 cm * 30.4 cm = 340.48 cm^2 (rounded to two decimal places).
The increase in the area is 340.48 cm^2 - 133 cm^2 = 207.48 cm^2 (rounded to two decimal places).
To find the percentage increase, we divide the increase in area by the original area and multiply by 100.
Percentage increase = (207.48 cm^2 / 133 cm^2) * 100 = 155.97% (rounded to two decimal places).
Therefore, the correct answer is not provided.