Rita and sita start jogging at the same point but in opposite directions.If the rate of one jogger is 2 mph faster than the other.After three hours,they are 30 miles apart,what is the rate of faster logger?
3(x-2 + x) = 30
4
5
To find the rate of the faster jogger, we need to first set up a system of equations based on the given information.
Let's assume that Rita's speed is x mph, and Sita's speed is (x + 2) mph. Since they are jogging in opposite directions, their combined speed will be (x + x + 2) mph, which is equal to 2x + 2 mph.
In three hours, the distance covered by Rita will be 3x miles, and by Sita will be 3(x + 2) miles. Since they are 30 miles apart, we can write the equation:
3x + 3(x + 2) = 30
Simplifying the equation, we have:
3x + 3x + 6 = 30
6x + 6 = 30
6x = 30 - 6
6x = 24
x = 24/6
x = 4
Therefore, Rita's rate is 4 mph, and Sita's rate is (4 + 2) mph = 6 mph. The rate of the faster jogger is 6 mph.