BC Place has 16 gates. In how many ways can you enter and leave the stadium by any gate?

I'm not sure if this this is a combination or a permutation. I think it's a permutation and my answer is 256 ways.

Thanks for the help.

you are correct

To find the number of ways you can enter and leave the BC Place stadium through any gate, you need to consider that the entry and exit gates are separate events.

As you correctly pointed out, this is a permutation problem because the order in which you enter and exit the stadium matters.

To calculate the number of ways, you need to find the total number of permutations of entering and exiting gates.

Since you have 16 gates and can enter and leave through any gate, you have 16 choices for both entering and exiting the stadium. Therefore, the total number of ways is calculated by multiplying the number of choices for entering by the number of choices for exiting:

16 choices for entering x 16 choices for exiting = 16 x 16 = 256

Therefore, your answer of 256 ways is correct.

To determine the number of ways to enter and leave the stadium through any of the 16 gates, we need to consider whether the order of entry and exit matters or not.

If the order matters, meaning that entering through one gate and exiting through another is considered a different scenario than entering through the second gate and exiting through the first, then we are dealing with permutations.

If the order does not matter, meaning that entering and exiting through different gates is considered the same regardless of the order, then we are dealing with combinations.

In this case, since you mentioned that you think it's a permutation, we will consider the order of entry and exit to be significant.

To calculate the number of permutations, we need to determine the number of choices for each step (entry and exit) and multiply them together.

Since there are 16 gates for both entry and exit, there are 16 choices for each step. Therefore, the total number of permutations is calculated as:

16 (choices for entry) * 16 (choices for exit) = 256

So, your answer of 256 ways is correct if the order matters in this scenario.