I just need a base to start to help teach my child:
Find the fraction:
If 1 is added to it's numerator, then it is equivalent to 1/3. And if 1 is added to it's denominator, then it is equivalent to 1/4
(n+1)/d = 1/3
n/(d+1) = 1/4
If that's too hard to work through, then just consider that
5/15 = 1/3
4/16 = 1/4
Manny is there a way we can speak thur email I have a question about your post.
To find the fraction, we can use algebraic equations. Let's assume the fraction is represented as x/y.
According to the given information, if we add 1 to the numerator, it becomes x + 1. And if we add 1 to the denominator, it becomes y + 1.
From the first condition, we have the equation: (x + 1) / y = 1/3
And from the second condition, we have the equation: x / (y + 1) = 1/4
To solve these equations simultaneously, we can use a method called cross-multiplication. Multiply the numerator on one side by the denominator on the other side, and equate the two resulting expressions.
For the first equation, (x + 1) / y = 1/3, we can cross-multiply to get:
3(x + 1) = y
For the second equation, x / (y + 1) = 1/4, cross-multiplying gives us:
4x = y + 1
Now we have a system of two equations:
3(x + 1) = y
4x = y + 1
We can solve this system of equations using various methods, such as substitution or elimination. Let's use substitution:
From the second equation, rearrange it to solve for y:
y = 4x - 1
Now substitute this value of y into the first equation:
3(x + 1) = 4x - 1
Expand the parentheses:
3x + 3 = 4x - 1
Move all the terms involving x to one side:
3 + 1 = 4x - 3x
4 = x
Now substitute this value of x back into either of the original equations to solve for y:
y = 4(4) - 1
y = 15
Therefore, the fraction is 4/15.