The area of a triangle is 25 cm squared. The base is twice the hight find the hight of a triangle.
please help me I cant do it without a help!!!
B = 2H
25 = .5HB
Substitute 2H for B in the second equation and solve for H.
25=x(x)2 over 2
=25.2
=50
50=x(x)2
=x(x)2-50
is this right? I don't know the factor of 50 and I don't know whats next
help!!!!!!!!!!!!!!!
To find the height of a triangle, given the area and the ratio of the base to height, you can use the formula for the area of a triangle, which is:
Area = (base * height) / 2
In this case, you are given that the area of the triangle is 25 cm². Let's denote the height of the triangle as "h" and the base as "2h" since the base is twice the height. Substituting these values into the formula, we get:
25 = (2h * h) / 2
Simplifying further:
25 = h²
To solve for "h", we take the square root of both sides:
√25 = √h²
Simplifying:
5 = h
Therefore, the height of the triangle is 5 cm.