consider a point A situated 85cm north of a point charge -45*10-3c and a point B which is situated 60cm west of the charge determine VB-VA

V=kQ/r

and this is not a vector.

Qa=-45E-3 coulombs
distance from A to B=.6m

To determine the potential difference (VB-VA) between point B and point A, we need to calculate the individual electric potentials at each point using the formula:

V = k * (q / r)

where:
- V is the electric potential
- k is the electrostatic constant (k = 9 x 10^9 N m^2/C^2)
- q is the charge of the point charge
- r is the distance between the charge and the point

First, let's calculate the electric potential at point A. Given that point A is situated 85 cm north of the point charge (-45 x 10^-3 C):

rA = 85 cm = 0.85 m
q = -45 x 10^-3 C

Using the formula, we have:

VA = k * (q / rA)
= (9 x 10^9 N m^2/C^2) * (-45 x 10^-3 C / 0.85 m)
= -4.8 x 10^7 V

Now, let's calculate the electric potential at point B, which is situated 60 cm west of the point charge:

rB = 60 cm = 0.60 m

Using the formula, we have:

VB = k * (q / rB)
= (9 x 10^9 N m^2/C^2) * (-45 x 10^-3 C / 0.60 m)
= -6.8 x 10^7 V

Finally, we can find VB-VA:

VB-VA = -6.8 x 10^7 V - (-4.8 x 10^7 V)
= -6.8 x 10^7 V + 4.8 x 10^7 V
= -2.0 x 10^7 V

Therefore, the potential difference (VB-VA) between point B and point A is -2.0 x 10^7 V.

To determine VB-VA, we need to calculate the electric potential at points A and B due to the point charge. By using the formula for electric potential created by a point charge, we can find the potential at each point and then subtract them.

The formula for electric potential due to a point charge is:

V = k * (q / r)

where:
V is the electric potential
k is the Coulomb's constant (k = 9 * 10^9 N m^2 / C^2)
q is the magnitude of the charge
r is the distance between the charge and the point where we want to calculate the potential

Let's calculate the electric potential at point A first. Given:
q = -45 * 10^-3 C (negative sign indicates a negative charge)
r = 85 cm = 0.85 m

Plugging in the values:

VA = k * (q / r)
= (9 * 10^9 N m^2 / C^2) * (-45 * 10^-3 C / 0.85 m)

Using a calculator, we obtain the value of VA as follows:

VA ≈ -2.65 * 10^5 V

Now, let's calculate the electric potential at point B. Given:
q = -45 * 10^-3 C
r = 60 cm = 0.6 m

Plugging in the values:

VB = k * (q / r)
= (9 * 10^9 N m^2 / C^2) * (-45 * 10^-3 C / 0.6 m)

Using a calculator, we obtain the value of VB as follows:

VB ≈ -6 * 10^5 V

Finally, we can determine VB-VA:

VB-VA = (-6 * 10^5 V) - (-2.65 * 10^5 V)
= -6 * 10^5 V + 2.65 * 10^5 V
= -3.35 * 10^5 V

So, VB-VA is approximately -3.35 * 10^5 V.