A box contain 40 pens of equal sizes.10 of them are green and 18 are red.if a pen is chosen at random from the box,what is the probability that is neither green nor red? Soln total number of pens=40 number of green pens=10 number of red pens=18 number of other pen=? =10+18=28 =40-28=12 =12/40=3/10 Therefore the probability of the other pen is 3/4.

12 pens out of 40 are neither red nor green

a randomly selected pen has a 12/40 or .3 probability of being in this group

not sure where 3/4 comes from...

2. A box contain 40 pens of equal size. 10 of them are green and 18 are red. If a pen is chosen at random from the box what is the probability that if 2 students are chosen at random from the class, one would pass and the other would fail

Total number of pens =40

3/10

Sorry, I made a mistake in my previous response. Here's the correct solution:

The probability that a randomly chosen pen is neither green nor red is the probability that it is blue, black, or some other color. Let's say there are 12 pens that fit this description. Then:

- The probability of choosing a red pen is 18/40
- The probability of choosing a green pen is 10/40
- The probability of choosing a pen that is neither red nor green is 12/40

If we want to find the probability that if 2 students are chosen at random from the class, one student would pass and the other would fail, we need more information about the students. The information given is only about the pens, not the students. Can you please provide more information or clarify the question?

Well, it seems like there's a little mix-up in your calculations. Let's fix that together, shall we?

To find the probability of choosing a pen that is neither green nor red, we need to determine the number of pens that fit that description and divide it by the total number of pens in the box.

The total number of pens in the box is indeed 40. However, the number of green pens is 10, and the number of red pens is 18. So, if we add those up, we get 10 + 18 = 28.

To find the number of pens that are neither green nor red, we subtract this number from the total: 40 - 28 = 12.

So, the number of other pens is actually 12, not 3.

Now we can calculate the probability by taking the number of other pens (12) and dividing it by the total number of pens (40): 12/40 = 3/10.

Therefore, the probability of choosing a pen that is neither green nor red is actually 3/10, not 3/4.

Hope that clears things up!

To find the probability that the chosen pen is neither green nor red, we need to know the total number of pens in the box, the number of green pens, and the number of red pens.

Given:
Total number of pens = 40
Number of green pens = 10
Number of red pens = 18

To find the number of pens that are neither green nor red, we subtract the number of green and red pens from the total number of pens:
Number of other pens = Total number of pens - Number of green pens - Number of red pens
= 40 - 10 - 18
= 12

The probability of selecting a pen that is neither green nor red is equal to the number of other pens divided by the total number of pens:
Probability = Number of other pens / Total number of pens
= 12 / 40

Simplifying the fraction, we get:
Probability = 3 / 10

Therefore, the probability of selecting a pen that is neither green nor red is 3/10.