A 37.0-kg crate rests on a level floor. A horizontal force of 50.0 N accelerates the crate at 1.00 m/s2.

Calculate the frictional force on the crate.

Calculate the coefficient of kinetic friction between the crate and the floor.

I got the normal force, 363 N. Now just need help with these two following problems. Please and thank you!

50-friction=37*1

friction=13 N
13=mu*37*9.8

mu= 13/(37*9.8)

To calculate the frictional force on the crate, you can use the equation for force:

frictional force = force applied - force of motion

In this case, the force applied is 50.0 N (the horizontal force) and the force of motion can be calculated using Newton's second law:

force of motion = mass * acceleration

So, substituting the given values:

force of motion = 37.0 kg * 1.00 m/s^2 = 37.0 N

Now, you can calculate the frictional force:

frictional force = 50.0 N - 37.0 N = 13.0 N

Therefore, the frictional force on the crate is 13.0 N.

To calculate the coefficient of kinetic friction between the crate and the floor, you need to use the formula:

coefficient of kinetic friction = frictional force / normal force

The normal force can be calculated using the equation:

normal force = mass * acceleration due to gravity

Substituting the given values:

normal force = 37.0 kg * 9.8 m/s^2 = 363.6 N (approximately)

Now, you can calculate the coefficient of kinetic friction:

coefficient of kinetic friction = 13.0 N / 363.6 N ≈ 0.036

Therefore, the coefficient of kinetic friction between the crate and the floor is approximately 0.036.

To calculate the frictional force on the crate, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, the net force is the horizontal force applied to the crate minus the frictional force:

Net force = Applied force - Frictional force

Given:
Mass of the crate (m) = 37.0 kg
Applied force (F) = 50.0 N
Acceleration (a) = 1.00 m/s²

Using Newton's second law, we can rearrange the equation to solve for the frictional force:

Frictional force = Applied force - Net force

Net force = mass × acceleration
Net force = 37.0 kg × 1.00 m/s²
Net force = 37.0 N

Frictional force = 50.0 N - 37.0 N
Frictional force = 13.0 N

Therefore, the frictional force on the crate is 13.0 N.

To calculate the coefficient of kinetic friction between the crate and the floor, you can use the formula:

Coefficient of kinetic friction (μ) = Frictional force / Normal force

Given:
Frictional force = 13.0 N
Normal force = 363 N

Coefficient of kinetic friction = 13.0 N / 363 N
Coefficient of kinetic friction ≈ 0.036

Therefore, the coefficient of kinetic friction between the crate and the floor is approximately 0.036.