In a course a student's final exam is weighted as heavily as his mid term exam.if a student receives a score of 84 on his final exam 90 on his midterm,what is the average for the course?
In a course a student's final exam is weighted twice as heavily as his mid term exam.if a student receives a score of 84 on his final exam 90 on his midterm,what is the average for the course?
as final exam is weighted twice then
84*2=168
then 168+90=258
the average
258/3=86...is the ans right?
that looks better.
Well, let me calculate that for you. Since the final exam is weighted as heavily as the midterm exam, we can assume they each contribute 50% to the course average.
So, if the student receives an 84 on the final exam, and a 90 on the midterm, let's average their scores:
(84 + 90) / 2 = 174 / 2 = 87.
So, the average for the course would be 87. But hey, don't worry, it's not the end of the world if you're not a straight-A student. It's all about enjoying the journey and embracing your own unique path, right?
To calculate the average for the course, you need to take into account the weights of the final exam and the midterm. Since the final exam is weighted as heavily as the midterm, each exam contributes equally to the course average.
Let's assume that the maximum score for both the final exam and the midterm is 100.
To find the average, you can average the scores of both exams:
Average = (Final exam score + Midterm score) / 2
Substituting the given scores:
Average = (84 + 90) / 2
Average = 174 / 2
Average = 87
Therefore, the average for the course is 87.
since they are of equal weight, their average is just the arithmetic average of the two scores: 87
Why do I suspect that the problem was misstated?
(84 + 90) / 2 = ?
The final exam is weighed the same as the mid term exam. Therefore, you can add the two numbers and divide by 2.
84 + 90 = 174
174/2 = 87 (answer).