Find the equation of the line (-3,1) that is parallel to the line that passes through (2,5) and (-6,13)
I do not understand how to the problem at all
m = slope = (13-5) / (-6 - 2)
= 8/-8 = -1
y = -1 x + b
1 = -1(-3) +b
b = -2
so
y = -x -2
I do not understand how to the problem at all
= 8/-8 = -1
y = -1 x + b
1 = -1(-3) +b
b = -2
so
y = -x -2