What is the percent of aluminum in Al2(SO4)3?
A. 15.8%
B. 28.1%
C. 56.7%
D. 54.0%
C?
No. Work it out, stop guessing.
Ok done A?
A is correct at 15.77 rounded to 15.8%
Thank yo sooooo much :D
To determine the percent of aluminum in Al2(SO4)3, we need to calculate the molar mass of aluminum and the molar mass of Al2(SO4)3.
The molar mass of aluminum (Al) is 26.98 g/mol. In Al2(SO4)3, we have 2 atoms of aluminum (Al) and 3 molecules of sulfate (SO4). The molar mass of sulfate (SO4) is 96.06 g/mol.
Now, we can calculate the molar mass of Al2(SO4)3:
Molar mass of Al2(SO4)3 = (2 * molar mass of Al) + (3 * molar mass of SO4)
= (2 * 26.98 g/mol) + (3 * 96.06 g/mol)
= 53.96 g/mol + 288.18 g/mol
= 342.14 g/mol
To find the percent of aluminum in Al2(SO4)3, we divide the molar mass of aluminum by the molar mass of Al2(SO4)3 and multiply by 100.
Percent of aluminum = (molar mass of Al / molar mass of Al2(SO4)3) * 100
= (26.98 g/mol / 342.14 g/mol) * 100
≈ 7.89%
Therefore, the correct answer is not listed among the options provided.