A light spring of force constant 8N/m is cut into two equal parts and then are connected in parallel the equivalent force constant will be what of the system. Solve this problem
the force constants add in parallel
16 N/m
WE WILL GET TWO SPRINGS WITH THE SAME SPRING CONSTANT SO JUST MULTIPLY "k" WITH 2
UR ANSWER WILL BE 8*2=16N/m
To solve this problem, we first need to understand how springs behave when they are connected in parallel.
When two springs are connected in parallel, it means that they are connected side by side to the same point. In this configuration, the effective force constant of the system is the sum of the force constants of the individual springs.
Let's denote the force constant of the original spring as k. Since we are cutting the spring into two equal parts, each part will have a force constant of k/2.
When these two springs are connected in parallel, their force constants add up. Therefore, the equivalent force constant, k(eq), of the system is given by:
k(eq) = (k/2) + (k/2)
= k
In other words, when two equal springs are connected in parallel, the equivalent force constant of the system remains the same as the original force constant of each spring.
In your case, the original spring has a force constant of 8 N/m. Hence, the equivalent force constant of the system when the two equal parts are connected in parallel will also be 8 N/m.