How do we do the calculations when carrying out an experiment on titrating 99% of 0.1molar of NaOH and 99% of 0.1molar of Sulphuric acid in a 1 litre?
Your question (are these two questions) is too general. What do you want? pH, OH or something else. What are you titrating it with; i.e., you need to know the final volume.
Example. 0.1mol NaOH titrated with 0.1M HCl.
0.1 x 0.99 = 0.099 titrated.
That leaves 0.1-0.099 = 0.001 mols NaOH
It will take 0.099 mol of the HCl to titrate 99% of the NaOH. The volume will be 1000 of the NaOH + 990 mL of the HCl = 1990 mL total volume so (OH^-) = 0.001 mol/1.990 L = ?