The density of water at 40 C is 1000 kg/ m3. What is the density of water at 900C. Use β= 210x10-6 C0.

i don't know the answer guys..please help me out

Water at 900 is called steam and it can have a wide variety of densities based on pressure.

Answer is 982

To find the density of water at 90°C using the given coefficient of thermal expansion (β), we can use the formula:

ρ2 = ρ1 / (1 + β * (T2 - T1))

Where:
ρ1 = density of water at initial temperature (40°C)
T1 = initial temperature (40°C)
T2 = final temperature (90°C)
β = coefficient of thermal expansion (210x10^-6 C^-1)
ρ2 = density of water at final temperature (90°C)

Plugging in the values:

ρ2 = 1000 kg/m^3 / (1 + (210x10^-6 C^-1) * (90°C - 40°C))

Simplifying:

ρ2 = 1000 kg/m^3 / (1 + (210x10^-6 C^-1) * 50°C)

ρ2 = 1000 kg/m^3 / (1 + 0.000021 C^-1 * 50°C)

ρ2 = 1000 kg/m^3 / (1 + 0.00105)

ρ2 = 1000 kg/m^3 / 1.00105

ρ2 ≈ 999.049 kg/m^3

Therefore, the density of water at 90°C is approximately 999.049 kg/m^3.